4sin^2A+1=sin^2A+2

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Solution for 4sin^2A+1=sin^2A+2 equation: 


Simplifying
4sin2A + 1 = sin2A + 2

Reorder the terms:
1 + 4in2sA = sin2A + 2

Reorder the terms:
1 + 4in2sA = 2 + in2sA

Solving
1 + 4in2sA = 2 + in2sA

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1in2sA' to each side of the equation.
1 + 4in2sA + -1in2sA = 2 + in2sA + -1in2sA

Combine like terms: 4in2sA + -1in2sA = 3in2sA
1 + 3in2sA = 2 + in2sA + -1in2sA

Combine like terms: in2sA + -1in2sA = 0
1 + 3in2sA = 2 + 0
1 + 3in2sA = 2

Add '-1' to each side of the equation.
1 + -1 + 3in2sA = 2 + -1

Combine like terms: 1 + -1 = 0
0 + 3in2sA = 2 + -1
3in2sA = 2 + -1

Combine like terms: 2 + -1 = 1
3in2sA = 1

Divide each side by '3n2sA'.
i = 0.3333333333n-2s-1A-1

Simplifying
i = 0.3333333333n-2s-1A-1

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